Optimal. Leaf size=163 \[ \frac {7 i a^4 \sec ^3(c+d x)}{8 d}+\frac {21 a^4 \tanh ^{-1}(\sin (c+d x))}{16 d}+\frac {21 i \sec ^3(c+d x) \left (a^4+i a^4 \tan (c+d x)\right )}{40 d}+\frac {21 a^4 \tan (c+d x) \sec (c+d x)}{16 d}+\frac {3 i \sec ^3(c+d x) \left (a^2+i a^2 \tan (c+d x)\right )^2}{10 d}+\frac {i a \sec ^3(c+d x) (a+i a \tan (c+d x))^3}{6 d} \]
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Rubi [A] time = 0.16, antiderivative size = 163, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 4, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {3498, 3486, 3768, 3770} \[ \frac {7 i a^4 \sec ^3(c+d x)}{8 d}+\frac {21 a^4 \tanh ^{-1}(\sin (c+d x))}{16 d}+\frac {3 i \sec ^3(c+d x) \left (a^2+i a^2 \tan (c+d x)\right )^2}{10 d}+\frac {21 i \sec ^3(c+d x) \left (a^4+i a^4 \tan (c+d x)\right )}{40 d}+\frac {21 a^4 \tan (c+d x) \sec (c+d x)}{16 d}+\frac {i a \sec ^3(c+d x) (a+i a \tan (c+d x))^3}{6 d} \]
Antiderivative was successfully verified.
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Rule 3486
Rule 3498
Rule 3768
Rule 3770
Rubi steps
\begin {align*} \int \sec ^3(c+d x) (a+i a \tan (c+d x))^4 \, dx &=\frac {i a \sec ^3(c+d x) (a+i a \tan (c+d x))^3}{6 d}+\frac {1}{2} (3 a) \int \sec ^3(c+d x) (a+i a \tan (c+d x))^3 \, dx\\ &=\frac {i a \sec ^3(c+d x) (a+i a \tan (c+d x))^3}{6 d}+\frac {3 i \sec ^3(c+d x) \left (a^2+i a^2 \tan (c+d x)\right )^2}{10 d}+\frac {1}{10} \left (21 a^2\right ) \int \sec ^3(c+d x) (a+i a \tan (c+d x))^2 \, dx\\ &=\frac {i a \sec ^3(c+d x) (a+i a \tan (c+d x))^3}{6 d}+\frac {3 i \sec ^3(c+d x) \left (a^2+i a^2 \tan (c+d x)\right )^2}{10 d}+\frac {21 i \sec ^3(c+d x) \left (a^4+i a^4 \tan (c+d x)\right )}{40 d}+\frac {1}{8} \left (21 a^3\right ) \int \sec ^3(c+d x) (a+i a \tan (c+d x)) \, dx\\ &=\frac {7 i a^4 \sec ^3(c+d x)}{8 d}+\frac {i a \sec ^3(c+d x) (a+i a \tan (c+d x))^3}{6 d}+\frac {3 i \sec ^3(c+d x) \left (a^2+i a^2 \tan (c+d x)\right )^2}{10 d}+\frac {21 i \sec ^3(c+d x) \left (a^4+i a^4 \tan (c+d x)\right )}{40 d}+\frac {1}{8} \left (21 a^4\right ) \int \sec ^3(c+d x) \, dx\\ &=\frac {7 i a^4 \sec ^3(c+d x)}{8 d}+\frac {21 a^4 \sec (c+d x) \tan (c+d x)}{16 d}+\frac {i a \sec ^3(c+d x) (a+i a \tan (c+d x))^3}{6 d}+\frac {3 i \sec ^3(c+d x) \left (a^2+i a^2 \tan (c+d x)\right )^2}{10 d}+\frac {21 i \sec ^3(c+d x) \left (a^4+i a^4 \tan (c+d x)\right )}{40 d}+\frac {1}{16} \left (21 a^4\right ) \int \sec (c+d x) \, dx\\ &=\frac {21 a^4 \tanh ^{-1}(\sin (c+d x))}{16 d}+\frac {7 i a^4 \sec ^3(c+d x)}{8 d}+\frac {21 a^4 \sec (c+d x) \tan (c+d x)}{16 d}+\frac {i a \sec ^3(c+d x) (a+i a \tan (c+d x))^3}{6 d}+\frac {3 i \sec ^3(c+d x) \left (a^2+i a^2 \tan (c+d x)\right )^2}{10 d}+\frac {21 i \sec ^3(c+d x) \left (a^4+i a^4 \tan (c+d x)\right )}{40 d}\\ \end {align*}
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Mathematica [A] time = 2.09, size = 171, normalized size = 1.05 \[ -\frac {a^4 (\cos (4 c)-i \sin (4 c)) (\tan (c+d x)-i)^4 \sec ^2(c+d x) \left (-4608 i \cos (c+d x)+5 (90 \sin (c+d x)+155 \sin (3 (c+d x))-63 \sin (5 (c+d x))-512 i \cos (3 (c+d x)))+5040 \cos ^6(c+d x) \left (\log \left (\cos \left (\frac {1}{2} (c+d x)\right )-\sin \left (\frac {1}{2} (c+d x)\right )\right )-\log \left (\sin \left (\frac {1}{2} (c+d x)\right )+\cos \left (\frac {1}{2} (c+d x)\right )\right )\right )\right )}{3840 d (\cos (d x)+i \sin (d x))^4} \]
Antiderivative was successfully verified.
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fricas [B] time = 0.67, size = 364, normalized size = 2.23 \[ \frac {-630 i \, a^{4} e^{\left (11 i \, d x + 11 i \, c\right )} + 6670 i \, a^{4} e^{\left (9 i \, d x + 9 i \, c\right )} + 10116 i \, a^{4} e^{\left (7 i \, d x + 7 i \, c\right )} + 8316 i \, a^{4} e^{\left (5 i \, d x + 5 i \, c\right )} + 3570 i \, a^{4} e^{\left (3 i \, d x + 3 i \, c\right )} + 630 i \, a^{4} e^{\left (i \, d x + i \, c\right )} + 315 \, {\left (a^{4} e^{\left (12 i \, d x + 12 i \, c\right )} + 6 \, a^{4} e^{\left (10 i \, d x + 10 i \, c\right )} + 15 \, a^{4} e^{\left (8 i \, d x + 8 i \, c\right )} + 20 \, a^{4} e^{\left (6 i \, d x + 6 i \, c\right )} + 15 \, a^{4} e^{\left (4 i \, d x + 4 i \, c\right )} + 6 \, a^{4} e^{\left (2 i \, d x + 2 i \, c\right )} + a^{4}\right )} \log \left (e^{\left (i \, d x + i \, c\right )} + i\right ) - 315 \, {\left (a^{4} e^{\left (12 i \, d x + 12 i \, c\right )} + 6 \, a^{4} e^{\left (10 i \, d x + 10 i \, c\right )} + 15 \, a^{4} e^{\left (8 i \, d x + 8 i \, c\right )} + 20 \, a^{4} e^{\left (6 i \, d x + 6 i \, c\right )} + 15 \, a^{4} e^{\left (4 i \, d x + 4 i \, c\right )} + 6 \, a^{4} e^{\left (2 i \, d x + 2 i \, c\right )} + a^{4}\right )} \log \left (e^{\left (i \, d x + i \, c\right )} - i\right )}{240 \, {\left (d e^{\left (12 i \, d x + 12 i \, c\right )} + 6 \, d e^{\left (10 i \, d x + 10 i \, c\right )} + 15 \, d e^{\left (8 i \, d x + 8 i \, c\right )} + 20 \, d e^{\left (6 i \, d x + 6 i \, c\right )} + 15 \, d e^{\left (4 i \, d x + 4 i \, c\right )} + 6 \, d e^{\left (2 i \, d x + 2 i \, c\right )} + d\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 1.32, size = 237, normalized size = 1.45 \[ \frac {315 \, a^{4} \log \left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 1\right ) - 315 \, a^{4} \log \left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 1\right ) - \frac {2 \, {\left (75 \, a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{11} + 960 i \, a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{10} + 1175 \, a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9} - 4800 i \, a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{8} - 1890 \, a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} + 4480 i \, a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{6} - 1890 \, a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 1920 i \, a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} + 1175 \, a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 1728 i \, a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 75 \, a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 448 i \, a^{4}\right )}}{{\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 1\right )}^{6}}}{240 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.52, size = 324, normalized size = 1.99 \[ \frac {a^{4} \left (\sin ^{5}\left (d x +c \right )\right )}{6 d \cos \left (d x +c \right )^{6}}+\frac {a^{4} \left (\sin ^{5}\left (d x +c \right )\right )}{24 d \cos \left (d x +c \right )^{4}}-\frac {a^{4} \left (\sin ^{5}\left (d x +c \right )\right )}{48 d \cos \left (d x +c \right )^{2}}-\frac {a^{4} \left (\sin ^{3}\left (d x +c \right )\right )}{48 d}-\frac {13 a^{4} \sin \left (d x +c \right )}{16 d}+\frac {21 a^{4} \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{16 d}+\frac {4 i a^{4}}{3 d \cos \left (d x +c \right )^{3}}+\frac {8 i a^{4} \cos \left (d x +c \right )}{15 d}-\frac {4 i a^{4} \left (\sin ^{4}\left (d x +c \right )\right )}{15 d \cos \left (d x +c \right )^{3}}+\frac {4 i a^{4} \left (\sin ^{4}\left (d x +c \right )\right )}{15 d \cos \left (d x +c \right )}+\frac {4 i a^{4} \cos \left (d x +c \right ) \left (\sin ^{2}\left (d x +c \right )\right )}{15 d}-\frac {3 a^{4} \left (\sin ^{3}\left (d x +c \right )\right )}{2 d \cos \left (d x +c \right )^{4}}-\frac {3 a^{4} \left (\sin ^{3}\left (d x +c \right )\right )}{4 d \cos \left (d x +c \right )^{2}}-\frac {4 i a^{4} \left (\sin ^{4}\left (d x +c \right )\right )}{5 d \cos \left (d x +c \right )^{5}}+\frac {a^{4} \sec \left (d x +c \right ) \tan \left (d x +c \right )}{2 d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.51, size = 246, normalized size = 1.51 \[ -\frac {5 \, a^{4} {\left (\frac {2 \, {\left (3 \, \sin \left (d x + c\right )^{5} + 8 \, \sin \left (d x + c\right )^{3} - 3 \, \sin \left (d x + c\right )\right )}}{\sin \left (d x + c\right )^{6} - 3 \, \sin \left (d x + c\right )^{4} + 3 \, \sin \left (d x + c\right )^{2} - 1} - 3 \, \log \left (\sin \left (d x + c\right ) + 1\right ) + 3 \, \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 180 \, a^{4} {\left (\frac {2 \, {\left (\sin \left (d x + c\right )^{3} + \sin \left (d x + c\right )\right )}}{\sin \left (d x + c\right )^{4} - 2 \, \sin \left (d x + c\right )^{2} + 1} - \log \left (\sin \left (d x + c\right ) + 1\right ) + \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 120 \, a^{4} {\left (\frac {2 \, \sin \left (d x + c\right )}{\sin \left (d x + c\right )^{2} - 1} - \log \left (\sin \left (d x + c\right ) + 1\right ) + \log \left (\sin \left (d x + c\right ) - 1\right )\right )} - \frac {640 i \, a^{4}}{\cos \left (d x + c\right )^{3}} - \frac {128 i \, {\left (5 \, \cos \left (d x + c\right )^{2} - 3\right )} a^{4}}{\cos \left (d x + c\right )^{5}}}{480 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 7.16, size = 290, normalized size = 1.78 \[ \frac {21\,a^4\,\mathrm {atanh}\left (\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\right )}{8\,d}-\frac {\frac {5\,a^4\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{11}}{8}+a^4\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{10}\,8{}\mathrm {i}+\frac {235\,a^4\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^9}{24}-a^4\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^8\,40{}\mathrm {i}-\frac {63\,a^4\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^7}{4}+\frac {a^4\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6\,112{}\mathrm {i}}{3}-\frac {63\,a^4\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5}{4}-a^4\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4\,16{}\mathrm {i}+\frac {235\,a^4\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3}{24}+\frac {a^4\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2\,72{}\mathrm {i}}{5}+\frac {5\,a^4\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}{8}-\frac {a^4\,56{}\mathrm {i}}{15}}{d\,\left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{12}-6\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{10}+15\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^8-20\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6+15\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4-6\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+1\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ a^{4} \left (\int \left (- 6 \tan ^{2}{\left (c + d x \right )} \sec ^{3}{\left (c + d x \right )}\right )\, dx + \int \tan ^{4}{\left (c + d x \right )} \sec ^{3}{\left (c + d x \right )}\, dx + \int 4 i \tan {\left (c + d x \right )} \sec ^{3}{\left (c + d x \right )}\, dx + \int \left (- 4 i \tan ^{3}{\left (c + d x \right )} \sec ^{3}{\left (c + d x \right )}\right )\, dx + \int \sec ^{3}{\left (c + d x \right )}\, dx\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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